1. Identify the substituents on the benzene ring
The substituents on the benzene ring are:
- Ethyl ($-C_2H_5$)
- Fluoro ($-F$)
- Nitro ($-NO_2$)
2. Apply IUPAC Nomenclature Rules
- Numbering: The substituents should be numbered to give the lowest possible set of numbers. The priority of numbering is generally based on alphabetical order.
- Alphabetical Order: When naming the compound, the substituents are listed in alphabetical order.
Following these rules, the ethyl group will have a lower number.
Considering the order Fluoro, then Nitro is best.
3. Determine the correct numbering
If we start numbering from the Fluoro group, we have F at 1, $NO_2$ at 2, and ethyl at 4, giving us 1-Fluoro, 2-Nitro, 4-Ethyl.
If we start numbering such that ethyl gets number 1, we have Ethyl at 4, F at 1 and $NO_2$ at 2, giving us 4-Ethyl, 1-Fluoro, 2-Nitro.
According to alphabetical order and priority, it should be numbered such that numbering starts from the Fluoro group.
The molecule follows alphabetical order - Ethyl, Fluoro, Nitro.
We assign the lowest locant to Fluoro i.e., '1'.
The IUPAC name would then be 4-Ethyl-1-Fluoro-2-nitrobenzene.
Final Answer:
(A) 4-Ethyl-1-Fluoro-2-nitrobenzene
To name this compound, follow the IUPAC nomenclature rules:
The correct answer is (A) : 4-Ethyl-1-Fluoro-2-nitrobenzene.
The correct IUPAC name of the compound is:
Match List - I with List - II:
Choose the correct answer from the given below options
The circuit shown in the figure contains two ideal diodes \( D_1 \) and \( D_2 \). If a cell of emf 3V and negligible internal resistance is connected as shown, then the current through \( 70 \, \Omega \) resistance (in amperes) is:
Charges are uniformly spread on the surface of a conducting sphere. The electric field from the center of the sphere in a point outside the sphere varies with distance \( r \) from the center as