



Reactivity towards SN1 depends upon the stability of the carbocation.

Let's figure out which of these compounds will react the fastest via an $ \text{S}_\text{N}1 $ mechanism. Remember, the rate-determining step in an $ \text{S}_\text{N}1 $ reaction is the formation of a carbocation. The more stable the carbocation intermediate, the faster the reaction will proceed.
Analyzing the Carbocations Formed:
(1) Cyclohexylmethyl carbocation:
This is a primary carbocation ($ \text{1}^\circ $). Primary carbocations are generally unstable due to the lack of hyperconjugation and inductive stabilization from more alkyl groups.
(2) Cyclohexyl carbocation:
This is a secondary carbocation ($ \text{2}^\circ $). Secondary carbocations are more stable than primary carbocations due to more hyperconjugative and inductive effects.
(3) Bromobenzene:
If the bromine were to leave, it would form a phenyl carbocation. Phenyl carbocations are highly unstable because the positive charge resides in an $ sp^2 $ hybridized orbital, which is held more tightly to the nucleus, and the carbocation cannot be stabilized by resonance in the usual sense.
(4) 1-Bromo-1-phenylethane:
Loss of bromine would result in the formation of a benzylic secondary carbocation ($ \text{2}^\circ $ benzylic). Benzylic carbocations are particularly stable due to resonance with the benzene ring, which delocalizes the positive charge over several carbon atoms. Furthermore, it's also a secondary carbocation, benefiting from hyperconjugation and inductive effects from the methyl group.
Comparing the Stabilities of the Potential Carbocations:
The order of stability is as follows:
Benzylic $ \text{2}^\circ $ > $ \text{2}^\circ $ alkyl > $ \text{1}^\circ $ alkyl >> phenyl
Conclusion:
The carbocation formed from compound (4) is the most stable. This means that compound (4) will undergo $ \text{S}_\text{N}1 $ reaction at the fastest rate.
Final Answer:
The compound that reacts the fastest via an $ \text{S}_\text{N}1 $ mechanism is: $ \boxed{(4)} $
The reaction sequence given below is carried out with 16 moles of X. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of S produced is ____. 
Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80
A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. The ratio of the moment of inertia of the smaller sphere to that of the rest part of the sphere about the Y-axis is : 
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :
The current passing through the battery in the given circuit, is: 
Given below are two statements:
Statement I: The primary source of energy in an ecosystem is solar energy.
Statement II: The rate of production of organic matter during photosynthesis in an ecosystem is called net primary productivity (NPP).
In light of the above statements, choose the most appropriate answer from the options given below: