Reactivity towards SN1 depends upon the stability of the carbocation.
Let's figure out which of these compounds will react the fastest via an $ \text{S}_\text{N}1 $ mechanism. Remember, the rate-determining step in an $ \text{S}_\text{N}1 $ reaction is the formation of a carbocation. The more stable the carbocation intermediate, the faster the reaction will proceed.
Analyzing the Carbocations Formed:
(1) Cyclohexylmethyl carbocation:
This is a primary carbocation ($ \text{1}^\circ $). Primary carbocations are generally unstable due to the lack of hyperconjugation and inductive stabilization from more alkyl groups.
(2) Cyclohexyl carbocation:
This is a secondary carbocation ($ \text{2}^\circ $). Secondary carbocations are more stable than primary carbocations due to more hyperconjugative and inductive effects.
(3) Bromobenzene:
If the bromine were to leave, it would form a phenyl carbocation. Phenyl carbocations are highly unstable because the positive charge resides in an $ sp^2 $ hybridized orbital, which is held more tightly to the nucleus, and the carbocation cannot be stabilized by resonance in the usual sense.
(4) 1-Bromo-1-phenylethane:
Loss of bromine would result in the formation of a benzylic secondary carbocation ($ \text{2}^\circ $ benzylic). Benzylic carbocations are particularly stable due to resonance with the benzene ring, which delocalizes the positive charge over several carbon atoms. Furthermore, it's also a secondary carbocation, benefiting from hyperconjugation and inductive effects from the methyl group.
Comparing the Stabilities of the Potential Carbocations:
The order of stability is as follows:
Benzylic $ \text{2}^\circ $ > $ \text{2}^\circ $ alkyl > $ \text{1}^\circ $ alkyl >> phenyl
Conclusion:
The carbocation formed from compound (4) is the most stable. This means that compound (4) will undergo $ \text{S}_\text{N}1 $ reaction at the fastest rate.
Final Answer:
The compound that reacts the fastest via an $ \text{S}_\text{N}1 $ mechanism is: $ \boxed{(4)} $
The major products obtained from the reactions in List-II are the reactants for the named reactions mentioned in List-I. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.
The reaction sequence given below is carried out with 16 moles of X. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of S produced is ____.
Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80
Consider a water tank shown in the figure. It has one wall at \(x = L\) and can be taken to be very wide in the z direction. When filled with a liquid of surface tension \(S\) and density \( \rho \), the liquid surface makes angle \( \theta_0 \) (\( \theta_0 < < 1 \)) with the x-axis at \(x = L\). If \(y(x)\) is the height of the surface then the equation for \(y(x)\) is: (take \(g\) as the acceleration due to gravity)
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :