Question

The Complex hexamine platinum (IV) chloride will give ___ number of ions on ionization

• A. 3
• B. 5
• C. 2
• D. 4

Answer 1

The Correct Option is B

The complex hexamine platinum (IV) chloride, \(\text{[Pt(NH}_3\text{)}_6\text{]Cl}_4\), consists of a central platinum (IV) ion coordinated with six ammonia ligands (NH₃) and four chloride ions (Cl^-) as counterions.
When this complex dissociates in solution, it will release its constituent ions. The complex itself contains one platinum ion, six ammonia ligands, and four chloride ions.
Upon ionization, the hexamine platinum (IV) chloride complex will generate two types of ions:
\(\text{[Pt(NH}_3\text{)}_6]^{4+}\) ion: This is the cationic part of the complex, consisting of the platinum (IV) ion coordinated with six ammonia ligands. It carries a charge of +4.
Four Cl^- ions: These are the anionic counterions in the complex. Each chloride ion carries a charge of -1.
Therefore, the hexamine platinum (IV) chloride complex will give a total of five ions upon ionization: one \(\text{[Pt(NH}_3\text{)}_6]^{4+}\) cation and four Cl^- anions.
Hence, the correct answer is (B) 5.