Question:
The centre of a wheel rolling on a plane surface moves with a speed \( v_0 \). A particle on the rim of the wheel at the same level as the centre will be moving at speed
The centre of a wheel rolling on a plane surface moves with a speed \( v_0 \). A particle on the rim of the wheel at the same level as the centre will be moving at speed
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The total speed of a point on the rim of a rolling wheel is the resultant of the translational and rotational velocities.
Updated On: Jan 6, 2026
- zero
- \( v_0 \)
- \( 2v_0 \)
- \( \sqrt{2} v_0 \)
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The Correct Option is D
Solution and Explanation
Step 1: Relative velocity of particle on the wheel.
The speed of a particle on the rim is the vector sum of the translational speed of the wheel’s centre and the rotational speed due to the wheel’s rotation. The resultant speed is \( \sqrt{2} v_0 \).
Step 2: Conclusion.
The speed of the particle at the rim is \( \sqrt{2} v_0 \), which corresponds to option (4).
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