Question:
The cartesian product $ A\times A $ has $9$ elements among which are found $ (-1,0) $ and $ (0,1), $ then set $A$ = ?
The cartesian product $ A\times A $ has $9$ elements among which are found $ (-1,0) $ and $ (0,1), $ then set $A$ = ?
Updated On: Jun 23, 2024
- $ \{1,\,\,0\} $
- $ \{1,\,\,-1,\,\,\,0\} $
- $ \{\,0,\,\,-1\} $
- $ \{1,\,\,-1\} $
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The Correct Option is B
Solution and Explanation
Given, $ n(A\times A)=9\,\,\,\,\,\,\,\Rightarrow \,\,\,\,\,n(A)\times n(A)=9 $
which is possible when,
$ n(A)=3. $ i.e.,
set A contain only three elements i.e.,
$ A=\{1,-1,0\} $
So, $ A\times A $ contain
$ (-1,0) $ and $ (0,\,1) $
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Concepts Used:
Relations and functions
A relation R from a non-empty set B is a subset of the cartesian product A × B. The subset is derived by describing a relationship between the first element and the second element of the ordered pairs in A × B.
A relation f from a set A to a set B is said to be a function if every element of set A has one and only one image in set B. In other words, no two distinct elements of B have the same pre-image.
Representation of Relation and Function
Relations and functions can be represented in different forms such as arrow representation, algebraic form, set-builder form, graphically, roster form, and tabular form. Define a function f: A = {1, 2, 3} → B = {1, 4, 9} such that f(1) = 1, f(2) = 4, f(3) = 9. Now, represent this function in different forms.
- Set-builder form - {(x, y): f(x) = y2, x ∈ A, y ∈ B}
- Roster form - {(1, 1), (2, 4), (3, 9)}
- Arrow Representation
