Question

The brightness values of four pixels in the input image are shown in the table below. The image is rectified using nearest neighbor intensity interpolation, and the pixel at location \((5, 4)\) in the output image is to be filled with the value from coordinate \((5.3, 3.7)\) in the input image. The brightness value of the pixel at location \((5, 4)\) in the rectified output image is \rule{1.5cm{0.15mm}. (Answer in integer)} \begin{center} \begin{tabular}{|c|c|} \hline Location of pixels in input image & Brightness
(Row, Column) & Value
\hline (5, 3) & 9
\hline (5, 4) & 11
\hline (6, 3) & 14
\hline (6, 4) & 12
\hline \end{tabular} \end{center}

Hint:

In nearest neighbor interpolation, simply round the coordinates to the nearest integers and pick the corresponding pixel value.

Answer 1

Correct Answer: 11

Using nearest neighbor interpolation, the point \((5.3, 3.7)\) is rounded to the nearest integer pixel coordinate. \[ {Nearest neighbor to } (5.3, 3.7) = (5, 4) \] From the table, the brightness value at location \((5, 4)\) is: \[ \boxed{11} \] Final Answer: \fbox{11}