Question

The bond order values of anions of sodium peroxide and potassium super oxide are respectively

• A. 1, 1.5
• B. 2, 0.5
• C. 0.5, 1
• D. 2, 0.5

Hint:

Use MOT (Molecular Orbital Theory) for calculating bond order in oxygen species.
Peroxide (O$_2^{2-}$) → BO = 1; Superoxide (O$_2^-$) → BO = 1.5.

Answer 1

The Correct Option is A

Sodium peroxide contains the peroxide ion (O$_2^{2-}$) and potassium superoxide contains the superoxide ion (O$_2^-$). Bond order formula: \[ \text{Bond Order} = \frac{(N_b - N_a)}{2} \] For O$_2^{2-}$: It has 18 electrons (16 + 2), so bond order = 1. For O$_2^-$: It has 17 electrons, so bond order = 1.5.