Question:

The binding energy per nucleon, for nuclei with atomic mass number $A > 100$ decreases with $A$. The nuclear forces are weak for heavier nuclei.

Updated On: Feb 7, 2024
  • If both assertion and reason are true and reason is the correct explanation of the assertion
  • If both assertion and reason are true but reason is not the correct explanation of the assertion
  • If assertion is true, but reason is false
  • Both assertion and reason are false statements
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The Correct Option is B

Solution and Explanation

The binding energy per nucleus is determined by dividing the binding energy of the nucleus by the number of nucleons it contains. Elements with intermediate atomic masses have the greatest binding energies per nucleon and are therefore the most stable.
The decrease in binding energy per nucleon for heavy nuclei $(A > 100)$ due to increase in coulomb repulsion between the protons inside the nucleus.
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Concepts Used:

Nuclei

In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.

Read More: Nuclei

Following are the terms related to nucleus:

  1. Atomic Number
  2. Mass Number
  3. Nuclear Size
  4. Nuclear Density
  5. Atomic Mass Unit