The average velocity of a freely falling body is numerically equal to half of the acceleration due to gravity. The velocity of the body as It reaches the ground is
Updated On: Sep 4, 2024
g
$\frac{g}{2}$
$\frac{g}{\sqrt{2}}$
$\sqrt{2}g$
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The Correct Option isA
Solution and Explanation
We have average velocity $=\frac{ g }{2}$
Since it is a free fall, average velocity, $v =\frac{ S }{ t }=\frac{\frac{1}{2} gt ^{2}}{ t }=\frac{ g }{2}$, where $t$ is the time