Question:

The average of five consecutive integers is 6. What is the largest of these integers?

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To solve average problems with consecutive integers, represent the integers algebraically and use the average formula to solve for the unknown.
Updated On: Sep 30, 2025
  • 7
  • 6
  • 12
  • 8
  • 10
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The Correct Option is A

Solution and Explanation

Step 1: Let the integers be \( x, x+1, x+2, x+3, x+4 \).
The average of these integers is given by: \[ \frac{x + (x+1) + (x+2) + (x+3) + (x+4)}{5} = 6. \]
Step 2: Simplify the equation.
\[ \frac{5x + 10}{5} = 6 \quad \Rightarrow \quad 5x + 10 = 30 \quad \Rightarrow \quad 5x = 20 \quad \Rightarrow \quad x = 4. \]
Step 3: Conclusion.
The five consecutive integers are \( 4, 5, 6, 7, 8 \). Therefore, the largest integer is 7.
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