Question:

The average of 5 consecutive numbers is n. If the next two numbers are also included the average will

Updated On: Aug 23, 2025
  • remain the same
  • increase by 1
  • increase by 1.4
  • increase by 2
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The Correct Option is B

Solution and Explanation

To solve the problem of determining how the average changes when including two additional numbers in the sequence, we need to start by understanding what is being asked: Given that the average of 5 consecutive numbers is \( n \), how does including the two subsequent consecutive numbers affect the average?
Let the 5 consecutive numbers be \( x, x+1, x+2, x+3, \) and \( x+4 \). The average of these numbers is given by:
\[ \text{Average} = \frac{x + (x+1) + (x+2) + (x+3) + (x+4)}{5} = \frac{5x + 10}{5} = x+2 \]
It's mentioned that this average is \( n \), so we have:
\[ x+2 = n \implies x = n-2 \]
Now, including the next two consecutive numbers, which are \( x+5 \) and \( x+6 \), makes the numbers:
\( x, x+1, x+2, x+3, x+4, x+5, x+6 \).
The new average is calculated as follows:
\[ \text{New average} = \frac{x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6)}{7} = \frac{7x + 21}{7} = x+3 \]
Since \( x = n-2 \), we substitute back to find:
\[ \text{New average} = (n-2) + 3 = n+1 \]
Therefore, the average increases by 1 when the next two numbers are included.
Thus, the correct choice is: increase by 1.
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