The area of the region bounded by the ellipse $$\frac{x^2}{16} + \frac{y^2}{9} = 1$$ is:
Step 1: Using the standard area formula for an ellipse.
The area of an ellipse is given by: \[ A = \pi a b \] where \( a^2 = 16 \Rightarrow a = 4 \) and \( b^2 = 9 \Rightarrow b = 3 \).
Step 2: Calculating the area.
\[ A = \pi (4)(3) = 12\pi \] Thus, the correct answer is (A).
Let $ y(x) $ be the solution of the differential equation $$ x^2 \frac{dy}{dx} + xy = x^2 + y^2, \quad x > \frac{1}{e}, $$ satisfying $ y(1) = 0 $. Then the value of $ 2 \cdot \frac{(y(e))^2}{y(e^2)} $ is ________.