The average thickness can be calculated using the formula:
\[ \text{Average thickness} = \frac{5 + 6 + 7}{3} = 6 \, \text{m} \]
The volume of the orebody is calculated by multiplying the area by the average thickness:
\[ \text{Volume} = \text{Area} \times \text{Average thickness} = 1500 \, \text{m}^2 \times 6 \, \text{m} = 9000 \, \text{m}^3 \]
The ore reserve is then calculated by multiplying the volume by the ore density:
\[ \text{Ore reserve} = \text{Volume} \times \text{Ore density} = 9000 \, \text{m}^3 \times 2.5 \, \text{tons/m}^3 = 22500 \, \text{tons} \]
The estimated ore reserve of the block is: 22500 tons.
Column I | Column II | ||
P. | Malanjkhand | 1. | Uranium ore |
Q. | Tummalapalle | 2. | Gold ore |
R. | Bhukia | 3. | Tin ore |
S. | Tosham | 4. | Copper ore |