Let the radius of the circle be \(r\) units.
The area of the circle is given by the formula \(A = \pi r^2\).
The circumference of the circle is given by the formula \(C = 2 \pi r\).
According to the problem, the area of the circle is numerically equal to its circumference.
Therefore, we have the equation:
$$ A = C $$
$$ \pi r^2 = 2 \pi r $$
To solve for \(r\), we can divide both sides of the equation by \( \pi r \) (assuming \(r \neq 0\)):
$$ \frac{\pi r^2}{\pi r} = \frac{2 \pi r}{\pi r} $$
$$ r = 2 $$
So, the radius of the circle is 2 units.
The diameter of the circle \(d\) is twice the radius:
$$ d = 2r $$
$$ d = 2 \times 2 $$
$$ d = 4 $$
Therefore, the diameter of the circle is 4 units.