Question:
The area in the first quadrant between \( x^2 + y^2 = 4 \) and \( y = \sin x \) is?
The area in the first quadrant between \( x^2 + y^2 = 4 \) and \( y = \sin x \) is?
Show Hint
To find the area between curves, set up the integral by subtracting the lower curve from the upper curve over the given limits.
Updated On: Jan 12, 2026
- \( \pi^2 \)
- \( 4 - 16 \)
- \( 16 \)
- \( 4 \)
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The Correct Option is D
Solution and Explanation
The area can be found by integrating the difference between the curves \( x^2 + y^2 = 4 \) and \( y = \sin x \) over the appropriate limits in the first quadrant.
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