Sc3+
Fe2+
Ti3+
Mn2+
(a) \(_{21}Sc^{3+}\) = 1s2, 2s2, 2p6, 3s2, 3p6
Because there are no unpaired electrons in the d-subshell, it is colourless.
(b) \(_{26}Fe^{2+}\)= 1s2, 2p6, 3s2, and 3d6
The presence of four unpaired electrons in the d-subshell is what gives it its hue.
(c) \(_{22}Ti^{3+}\) =1s2,2s2, 2p6, 3s2, and 3p6
Because there is one unpaired electron in the d-subshell, it is coloured.
(d) \(_{25}Mn^{2+}\)= 1s2, 2s2, 2p6, 3s2, and 3p6 3d5.
It has colour because the d-subshell contains five unpaired electrons.
Therefore, the correct option is (A): Sc3+
The d-block elements are placed in groups 3-12 and F-block elements with 4f and 5f orbital filled progressively. The general electronic configuration of d block elements and f- block elements are (n-1) d 1-10 ns 1-2 and (n-2) f 1-14 (n-1) d1 ns2 respectively. They are commonly known as transition elements because they exhibit multiple oxidation states because of the d-d transition which is possible by the availability of vacant d orbitals in these elements.
They have variable Oxidation States as well as are good catalysts because they provide a large surface area for the absorption of reaction. They show variable oxidation states to form intermediate with reactants easily. They are mostly lanthanoids and show lanthanoid contraction. Since differentiating electrons enter in an anti-penultimate f subshell. Therefore, these elements are also called inner transition elements.
Read More: The d and f block elements