Question:
The amplitude of the sinusoidially oscillating electric field of a plane wave is $ 60\, V/m $ . Then the amplitude of magnetic field is:
The amplitude of the sinusoidially oscillating electric field of a plane wave is $ 60\, V/m $ . Then the amplitude of magnetic field is:
Updated On: Jun 6, 2022
- $ 2\times {{10}^{2}}T $
- $ 6\times {{10}^{7}}T $
- $ 6\times {{10}^{2}}T $
- $ 2\times {{10}^{-7}}T $
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The Correct Option is D
Solution and Explanation
The instantaneous magnitudes of electric field (E) and magnetic field (B) are related as
$ \frac{E}{B}=c $ $ \Rightarrow $ $ B=\frac{E}{c} $
Given, $ E=60\,V/m,c=3\times {{10}^{8}}m/s $
$ \therefore $ $ B=\frac{60}{3\times {{10}^{8}}}=2\times {{10}^{-7}}T $
$ \frac{E}{B}=c $ $ \Rightarrow $ $ B=\frac{E}{c} $
Given, $ E=60\,V/m,c=3\times {{10}^{8}}m/s $
$ \therefore $ $ B=\frac{60}{3\times {{10}^{8}}}=2\times {{10}^{-7}}T $
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Concepts Used:
Displacement Current
Displacement current is a quantity appearing in Maxwell’s equations. Displacement current definition is defined in terms of the rate of change of the electric displacement field (D). It can be explained by the phenomenon observed in a capacitor.
