Question

The Allyl cyanide molecule contains:

• A. 9 sigma bonds, 4 pi bonds, and no lone pair
• B. 9 sigma bonds, 3 pi bonds, and one lone pair
• C. 8 sigma bonds, 5 pi bonds, and one lone pair
• D. 8 sigma bonds, 3 pi bonds, and two lone pairs

Hint:

Triple bonds contribute 1 sigma and 2 pi bonds, while double bonds contribute 1 sigma and 1 pi bond.

Answer 1

The Correct Option is B

Step 1: Understanding bond structure in allyl cyanide. 
- Allyl cyanide (\( CH_2=CH-CH_2-CN \)) consists of: 
1. A C=C double bond (1 sigma, 1 pi bond). 
2. A C≡N triple bond (1 sigma, 2 pi bonds). 
3. Single bonds (C-H, C-C, C-N) contributing sigma bonds. 
Step 2: Counting bonds and lone pairs. 
- Sigma bonds: 9. 
- Pi bonds: 3 (1 from C=C and 2 from C≡N). 
- Lone pairs: One on nitrogen.