Question:

The acceleration of any electron due to the magnetic field is

Updated On: Nov 4, 2024
  • $3.14\times10^{14} \,m/s^2$
  • $4.28\times10^{14} \,m/s^2$
  • $5.56\times10^{12}\, m/s^2$
  • $6.28\times10^{14}\, m/s^2$
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The Correct Option is D

Solution and Explanation

Answer (d) $6.28\times10^{14}\, m/s^2$
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