Question:

The acceleration of any electron due to the magnetic field is

Updated On: Nov 4, 2024

$3.14\times10^{14} \,m/s^2$
$4.28\times10^{14} \,m/s^2$
$5.56\times10^{12}\, m/s^2$
$6.28\times10^{14}\, m/s^2$

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The Correct Option is D

Solution and Explanation

Answer (d)

6.28\times10^{14}\, m/s^2

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