The acceleration of a moving body is found from the
- area under velocity - time graph
- area under displacement - time graph
- slope of distance ? time graph
- slope of velocity - time graph
The Correct Option is D
Solution and Explanation
Top Questions on Acceleration
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The acceleration due to gravity at a height of 6400 km from the surface of the earth is \(2.5 \, \text{ms}^{-2}\). The acceleration due to gravity at a height of 12800 km from the surface of the earth is (Radius of the earth = 6400 km)
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For the reaction:
$3Fe_{(s)} + 2O_2{(g)} \rightarrow Fe_3O_4{(s)}$
$\Delta H = -1650\,\text{kJ mol}^{-1}$, $\Delta S = -600\,\text{J K}^{-1} \text{mol}^{-1}$ at $300\,\text{K}$. What is the value of free energy change for the reaction at $300\,\text{K}$?
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- For the reaction: $$ 2A + B \rightarrow 2C + D $$ The following kinetic data were obtained for three different experiments performed at the same temperature: $$ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline \text{I} & 0.10 & 0.10 & 0.10 \\ \text{II} & 0.20 & 0.10 & 0.40 \\ \text{III} & 0.20 & 0.20 & 0.40 \\ \hline \end{array} $$ The total order and order in $[B]$ for the reaction are respectively:
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Concepts Used:
Acceleration
In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration.
