The given arithmetic progression (AP) is:
\(-10, -5, 0, 5, \dots\).
This is an arithmetic progression with the first term \( a = -10 \) and common difference \( d = 5 \).
The formula for the \( n \)-th term of an AP is: \\ \[ T_n = a + (n-1) \cdot d \] For the 15th term, substitute \( n = 15 \), \( a = -10 \), and \( d = 5 \): \[ T_{15} = -10 + (15-1) \cdot 5 = -10 + 14 \cdot 5 = -10 + 70 = 60 \] Thus, the 15th term of the AP is \(60\).
The correct option is (B): \(60\)
Let \( \alpha, \beta \) be the roots of the equation \( x^2 - ax - b = 0 \) with \( \text{Im}(\alpha) < \text{Im}(\beta) \). Let \( P_n = \alpha^n - \beta^n \). If \[ P_3 = -5\sqrt{7}, \quad P_4 = -3\sqrt{7}, \quad P_5 = 11\sqrt{7}, \quad P_6 = 45\sqrt{7}, \] then \( |\alpha^4 + \beta^4| \) is equal to: