Question:
\( \text{XeF}_4 \) disproportionate in water to give
\( \text{XeF}_4 \) disproportionate in water to give
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Disproportionation reactions occur when a compound is both oxidized and reduced simultaneously.
Updated On: Jan 12, 2026
- \( \text{Xe} + \text{HF} \)
- \( \text{Xe} + \text{XeO}_3 \)
- \( \text{XeO}_4 \) and HF
- \( \text{XeO}_2F_2 \) and \( \text{XeO}_3 \)
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The Correct Option is C
Solution and Explanation
Step 1: Disproportionation of \( \text{XeF}_4 \).
When xenon tetrafluoride (\( \text{XeF}_4 \)) is disproportionated in water, it gives xenon tetroxide (\( \text{XeO}_4 \)) and hydrofluoric acid (HF) as products. This is a typical disproportionation reaction of xenon compounds.
Step 2: Conclusion.
The correct answer is (C), \( \text{XeO}_4 \) and HF.
When xenon tetrafluoride (\( \text{XeF}_4 \)) is disproportionated in water, it gives xenon tetroxide (\( \text{XeO}_4 \)) and hydrofluoric acid (HF) as products. This is a typical disproportionation reaction of xenon compounds.
Step 2: Conclusion.
The correct answer is (C), \( \text{XeO}_4 \) and HF.
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