Question:
Surface mass density of a disc is given by $\sigma = kr^2$ (where r is distance from centre) find moment of inertia about axis passing through the centre and perpendicular to plane -
Surface mass density of a disc is given by $\sigma = kr^2$ (where r is distance from centre) find moment of inertia about axis passing through the centre and perpendicular to plane -
Updated On: Jul 7, 2022
- $\frac{k \pi r^6}{3} $
- $\frac{k \pi r^6}{6} $
- $\frac{ 2 k \pi r^6}{5} $
- $\frac{ 3 k \pi r^6}{5} $
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The Correct Option is A
Solution and Explanation
Answer (a) $\frac{k \pi r^6}{3} $
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Pascals Law
Pascal's law is also known as Pascal's principle further it can be called the principle of transmission of fluid pressure. Additionally, the applied external pressure is transmitted throughout the fluid without any loss in magnitude. The expression of Pascal's law is given as follows.
Δp = ρg x Δh
where
- Δp = the hydrostatic pressure, which is the difference in measured pressure between two points on the fluid. This accomplished pressure is a result of the fluid's total weight (in pascals Pa)
- ρ = the density of the fluid (in kilograms per cubic meter kg/ m3)
- g = the acceleration due to gravity (g = 9.8 m/ s2)
- Δh = the difference in the height of the measured points in the fluid container