Question

Suppose the two photographs, shown in Fig. had been taken at an interval of 10 seconds. If a distance of 100 metres is shown by 1 cm in these photographs, calculate the speed of the fastest car.

Answer 1

From the figures, we conclude that the distance covered by blue car is 2 cm.

So, the distance covered = 2 × 100 m = 200 m Time taken = 10 seconds
Speed = \(\frac{\text{Distance }}{ \text{Time}} = \frac{200 \,m }{ 10 \,s}\)  = 20 m / s