The correct options is (A): π(π₯1, π₯2, β¦ , π₯π ) = π’(π₯1, π₯2, β¦ , π₯π ) + (π’(π₯1, π₯2, β¦ , π₯π ))3 and (C): \(β(π₯_1, π₯_2, β¦ , π₯_π ) = (π’(π₯_1, π₯_2, β¦ , π₯_π )) ^{\frac{1}{n}}\)