Question:

Suppose that a 95% confidence interval states that population mean is greater than 100 and less than 300. Then the value of sample mean \((\bar{x})\) and margin of error (E) respectively are :

Updated On: May 11, 2025
  • 150, ±100
  • 100, ±100
  • 250, ±50
  • 200, ±100
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The Correct Option is D

Solution and Explanation

To find the sample mean and the margin of error, we start by identifying the boundaries of the 95% confidence interval given as greater than 100 and less than 300. These are the endpoints of the interval which can be represented as [100, 300].
The sample mean \(\bar{x}\) is the midpoint of the confidence interval. It is calculated using the formula:
\[ \bar{x} = \frac{\text{Lower Bound} + \text{Upper Bound}}{2} \]
Substituting the given bounds:
\[ \bar{x} = \frac{100 + 300}{2} = \frac{400}{2} = 200 \]
The margin of error (E) is the difference between the sample mean and either endpoint of the confidence interval. It can be calculated as:
\[ E = \text{Upper Bound} - \bar{x} \]
or equivalently:
\[ E = \bar{x} - \text{Lower Bound} \]
Using the sample mean:
\[ E = 300 - 200 = 100 \]
So, the sample mean \(\bar{x}\) is 200 and the margin of error E is ±100.
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