{"@context":"https://schema.org/","@type":"Quiz","dateCreated":"2024-06-21T12:11:43.926Z","dateModified":"2024-06-21T12:11:43.926Z","typicalAgeRange":"11-18","educationalLevel":"JIPMER MBBS","assesses":"Chemistry - Hydrocarbons","educationalAlignment":[{"@type":"AlignmentObject","alignmentType":"educationalTopic","targetName":"Hydrocarbons"},{"@type":"AlignmentObject","alignmentType":"educationalSubject","targetName":"Chemistry"},{"@type":"AlignmentObject","alignmentType":"educationalExam","targetName":"JIPMER MBBS"}],"name":"Quiz about Hydrocarbons","about":{"@type":"Thing","name":"Chemistry - Hydrocarbons"},"hasPart":[{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"intermediate","name":"Question About Hydrocarbons","text":"Suitable reagent for conversion of following reaction. $$CH_2=CH-CHO\\xrightarrow{?}CH_2=CH-CH_2-OH$$}","encodingFormat":"text/markdown","comment":{"@type":"Comment","text":"\"\""},"suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/markdown","text":"

\$NaBH_4\$

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":1,"encodingFormat":"text/markdown","text":"

\$Ni/H_2\$

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":2,"encodingFormat":"text/markdown","text":"

\$Zn/Hg/Cl\$

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":3,"encodingFormat":"text/markdown","text":"

Red \$P+HI\$

","comment":{"@type":"Comment","text":"\"\""}}],"acceptedAnswer":{"@type":"Answer","position":0,"encodingFormat":"text/markdown","text":"

\$NaBH_4\$

","comment":{"@type":"Comment","text":"\"\""},"answerExplanation":{"@type":"comment","text":"The correct option is (A): \$NaBH_4\$ ."}}}]}

Suitable reagent for conversion of following reaction.\(CH_2=CH-CHO\xrightarrow{?}CH_2=CH-CH_2-OH\)

The Correct Option is A

Solution and Explanation

Top Questions on Hydrocarbons

Questions Asked in JIPMER MBBS exam

Suitable reagent for conversion of following reaction.
\(CH_2=CH-CHO\xrightarrow{?}CH_2=CH-CH_2-OH\)