Step 1: Fix Row–2 using the F–B gap.
Since “B sits to the left of F” and “exactly two sit between B and F”, possible $(B,F)$ pairs are $(1,4)$, $(2,5)$, $(3,6)$.
But from (1) L is opposite to the person second to the left of F, so $F$ cannot be at $3$ or less. Testing gives only $F=4$ works consistently (shown below).
Step 2: Take $F=4 ⇒ B=1$. Determine $L$.
“Second to the left of F” (Row–2 faces north, so ‘left’ is towards lower indices) is seat $2$. Hence the person at Row–2, seat $2$ is opposite L. Therefore, L is at Row–1, seat $2$.
Step 3: Use the left/right count relation for $L$ and $P$.
For Row–1 (facing south), “left of L” means positions to L’s left (from L’s viewpoint), which are to our right.
Number left of $L$ $= 6 - \text{col}(L) = 6-2=4$.
So number right of $P$ (still Row–1) must be $4 ⇒ \text{col}(P)-1=4 ⇒ \text{col}(P)=5$.
Step 4: Place $N$ using “N is second to the right of P”.
Facing south, “right” is to our left. Hence $N$ is two seats to the left of $P$: $\text{col}(N)=5-2=3$.
Step 5: Place $O$ using “O and P are not neighbours”.
$P$ is at $5$; neighbours are $4$ and $6$. So $O\notin\{4,6\}$. Available seats in Row–1 are $\{1,4,6\}$; thus $O$ must be at $1$.
Step 6: Fix $Q$ using the $C$–opposite clue.
“$C$ sits opposite to the one who sits second to the left of $Q$.”
Row–1 faces south, so “second to the left of $Q$” is two to our right: seat $(\text{col}(Q)+2)$. This must be $\le 6$, so $\text{col}(Q)\le 4$.
Available seats are $\{4,6\}$, but $Q$ cannot be $6$ (would need $+2=8$). Hence $Q=4$.
Therefore the opposite seat for $C$ is Row–2, seat $6$.
Step 7: Complete Row–2 using E left of D (neither at ends).
We already have $B=1$, $F=4$, $C=6$. Remaining seats are $\{2,3,5\}$ for $\{A,D,E\}$ with $E$ immediately left of $D$. Only $(E,D)=(2,3)$ works (and neither is at an end). Thus $A=5$.
Row–2 (left $\to$ right): $B\ E\ D\ F\ A\ C$.
Step 8: Final layout and the position of $Q$ w.r.t. $L$.
Row–1 (south): $O\ L\ N\ Q\ P\ M$ (opposites align by column).
$Q$ is two seats to the right (our view) of $L$. Since Row–1 faces south, that is second to the left w.r.t. $L$.
\[
\boxed{\text{$Q$ is second to the left of $L$}}
\]