Question:
Stand electrode potential are Fe+2/Fe Eº = – 0.44 Fe+3/Fe+2 Eº = 0.77 If Fe+2, Fe+3 and Fe block re kept together, then
Stand electrode potential are Fe+2/Fe Eº = – 0.44 Fe+3/Fe+2 Eº = 0.77 If Fe+2, Fe+3 and Fe block re kept together, then
Updated On: Apr 15, 2024
- Fe^+3 increases
- Fe^+3 decreases
- Fe^+2/Fe^+3 reamins unchanged
- Fe^+2 decreases
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
The correct option is(B): Fe^+3 decreases.
The direction of the redox reaction is determined by the difference in standard electrode potentials (E° values), and it proceeds from the species with a lower E° value (Fe^2+) to the species with a higher E° value (Fe^3+), resulting in an increase in the concentration of Fe^3+ and a decrease in the concentration of Fe^2+.
Was this answer helpful?
0
0
Top Questions on Electrochemistry
- State Faraday’s second law of electrolysis. How much electricity is required in terms of Faraday for the reduction of 1 mole of $Cr_2\text{O}_7^{2-} \text{ to Cr}^{3+}$?
- CBSE CLASS XII - 2025
- Chemistry
- Electrochemistry
- Represent the cell in which the following reaction takes place:
\text{Mg(s)} + 2Ag^{+} (0.001 M) \rightarrow \text{Mg}^{2+} (0.100 M) + 2Ag(s)
Calculate E_{cell} if E^\circ_{cell} = 3.17 V. (log 10 = 1)- CBSE CLASS XII - 2025
- Chemistry
- Electrochemistry
- For a galvanic cell, the following half reactions are given. Decide, which will remain as reduction reaction and which will be reversed to become an oxidation reaction. Give reason for your answer.
(I) Cr3+ + 3e− → Cr(s); E° = −0.74 V
(II) Fe2+ + 2e− → Fe(s); E° = −0.44 V- CBSE CLASS XII - 2025
- Chemistry
- Electrochemistry
- Based on the data given above, give plausible reason for the variation of conductivity and molar conductivity with concentration.
Concentration of KCl solution (mol/L) Conductivity at 298.15 K (S cm-1) Molar Conductivity at 298.15 K (S cm2 mol-1) 1.000 0.1113 111.3 0.100 0.0129 129.0 0.010 0.00141 141.0 - CBSE CLASS XII - 2025
- Chemistry
- Electrochemistry
- Match the type of cell given in Column I with their use given in Column II.
Column I Column II i. Lead storage cell d. Inverter ii. Mercury cell b. Apollo Space Programme iii. Dry cell c. Wrist watch iv. Fuel cell a. Wall clock - CBSE CLASS XII - 2025
- Chemistry
- Electrochemistry
View More Questions
Questions Asked in NEET exam
- De-Broglie wavelength of an electron orbiting in the \(n = 2\) state of hydrogen atom is close to (Given Bohr radius = 0.052 nm):
- NEET (UG) - 2025
- de broglie hypothesis
- Which chromosome in the human genome has the highest number of genes?
- NEET (UG) - 2025
- Human genome
- In a certain camera, a combination of four similar thin convex lenses are arranged axially in contact. Then the power of the combination and the total magnification in comparison to one lens will be, respectively:
- NEET (UG) - 2025
- Images Formed By Lenses
AB is a part of an electrical circuit (see figure). The potential difference \(V_A - V_B\), at the instant when current \(i = 2\) A and is increasing at a rate of 1 amp/second is:
- NEET (UG) - 2025
- Electromagnetic Induction and Inductance
- A ball of mass 0.5 kg is dropped from a height of 10 m. The ball hits the ground and rises to a height of 1.5 m. The impulse imparted to the ball during its collision with the ground is : (Take \(g = 9.8 \, \text{m/s}^2\))
- NEET (UG) - 2025
- Collision and Impulse
View More Questions
Concepts Used:
Gibbs Free Energy
The energy associated with a chemical reaction that can be used to do work.It is the sum of its enthalpy plus the product of the temperature and the entropy (S) of the system.
The Gibbs free energy is the maximum amount of non-expansion work that can be extracted from a thermodynamically closed system. In completely reversible process maximum enthalpy can be obtained.
ΔG=ΔH−TΔS
The Conditions of Equilibrium
If both it’s intensive properties and extensive properties are constant then thermodynamic system is in equilibrium. Extensive properties imply the U, G, A.
