Molar Conductance (Λm) is given by:
Λm = κ × 1000 / C
where,
κ = specific conductance = \(6.3 \times 10^{-2}\) ohm-1 cm-1
C = concentration = 0.1 mol/L
Substituting the values:
Λm = \( \frac{6.3 \times 10^{-2} \times 1000}{0.1} = 630 \) ohm-1 cm2 mol-1
Correct Answer: 630 ohm-1 cm2 mol-1
For the given cell: \[ {Fe}^{2+}(aq) + {Ag}^+(aq) \to {Fe}^{3+}(aq) + {Ag}(s) \] The standard cell potential of the above reaction is given. The standard reduction potentials are given as: \[ {Ag}^+ + e^- \to {Ag} \quad E^\circ = x \, {V} \] \[ {Fe}^{2+} + 2e^- \to {Fe} \quad E^\circ = y \, {V} \] \[ {Fe}^{3+} + 3e^- \to {Fe} \quad E^\circ = z \, {V} \] The correct answer is:
Read the following statements: Statement I: All vertebrates develop a row of vestigial gill slits during embryonic stage.
Statement II: Embryos always pass through the adult stages of other animals.