Question

Specific Conductance of 0.1 M HNO₃ is 6.3 x 10^-2 ohm ^-1 cm^-1. The molar conductance of the solution is

• A. 6300 ohm^-1 cm² mol^-1
• B. 630 ohm^-1 cm² mol^-1
• C. 63.0 ohm^-1 cm² mol^-1
• D. 315 ohm^-1 cm² mol^-1

Answer 1

The Correct Option is A

Molar Conductance (Λ_m) is given by:
Λ_m = κ × 1000 / C

where,
κ = specific conductance = \(6.3 \times 10^{-2}\) ohm^-1 cm^-1
C = concentration = 0.1 mol/L

Substituting the values:
Λ_m = \( \frac{6.3 \times 10^{-2} \times 1000}{0.1} = 630 \) ohm^-1 cm² mol^-1

Correct Answer: 630 ohm^-1 cm² mol^-1

Answer 2

Given: 

• Specific conductance \( \kappa = 6.3 \times 10^{-2} \, \text{ohm}^{-1} \, \text{cm}^{-1} \)
• Concentration \( C = 0.1 \, \text{mol L}^{-1} \)

Formula:
Molar conductance \( \Lambda_m = \frac{\kappa \times 1000}{C} \)

Substitute the values:
$$ \Lambda_m = \frac{6.3 \times 10^{-2} \times 1000}{0.1} = \frac{63}{0.1} = 630 \, \text{ohm}^{-1} \, \text{cm}^2 \, \text{mol}^{-1} $$

Correct answer: 630 ohm^-1 cm² mol^-1