Question:
Solve the following riddle:
I am a number, Tell my identity!
Take me seven times over, And add a fifty!
To reach a triple century, You still need forty!
Solve the following riddle:
I am a number, Tell my identity!
Take me seven times over, And add a fifty!
To reach a triple century, You still need forty!
Updated On: Apr 1, 2024
Hide Solution
Verified By Collegedunia
Solution and Explanation
Let the number be n According to the question, 7n+50+40=300
Thus, the required number is 30.
Was this answer helpful?
1
0
Top Questions on A Mind-Reading Game
Solve the following equations by trial and error method: (i) 5p + 2 = 17 (ii) 3m – 14 = 4
- CBSE Class VII
- Mathematics
- A Mind-Reading Game
Write equations for the following statements:
(i) The sum of numbers x and 4 is 9.
(ii) 2 subtracted from y is 8.
(iii) Ten times a is 70.
(iv) The number b divided by 5 gives 6.
(v) Three-fourth of t is 15.
(vi) Seven times m plus 7 gets you 77.
(vii) One-fourth of a number x minus 4 gives 4.
(viii) If you take away 6 from 6 times y, you get 60.
(ix) If you add 3 to one-third of z, you get 30- CBSE Class VII
- Mathematics
- A Mind-Reading Game
- Set up equations and solve them to find the unknown numbers in the following cases:
(a) Add 4 to eight times a number; you get 60.
(b) One-fifth of a number minus 4 gives 3.
(c) If I take three-fourths of a number and add 3 to it, I get 21.
(d) When I subtracted 11 from twice a number, the result was 15.
(e) Munna subtracts thrice the number of notebooks he has from 50, he finds the result to be 8.
(f) Ibenhal thinks of a number. If she adds 19 to it and divides the sum by 5, she will get 8.
(g) Anwar thinks of a number.If he takes away 7 from \(\frac{5}{2}\) of the number,the result is 23.- CBSE Class VII
- Mathematics
- A Mind-Reading Game
- Write the following equations in statement forms:
(i)p+4=15
(ii)m-7=3
(iii)2m=7
(iv)\(\frac{m}{5}\)=3
(v)\(\frac{3m}{5}\)=6
(vi)3p+4=25
(vii)4p-2=18
(viii)\(\frac{p}{2}\)+2=8- CBSE Class VII
- Mathematics
- A Mind-Reading Game
- Solve the following equations:
(a) 10p = 100
(b) 10p + 10 = 100
(c)\(\frac{p}{4}\)=5
(d) \(\frac{-p}{3}\)=5
(e)\(\frac{3p}{4}\)=6
(f)3s=-9
(g)3s+12=0
(h)3s=0
(i)2q=6
(j)2q-6=0
(k)2q+6=0
(l)2q+6=12- CBSE Class VII
- Mathematics
- A Mind-Reading Game
View More Questions
Questions Asked in CBSE Class VII exam
- ∆ ABC is right angled at A (Fig 9.16). AD is perpendicular to BC. If AB = \(5\) cm, BC = \(13\) cm and AC = \(12\) cm, Find the area of ∆ ABC. Also find the length of AD.
- CBSE Class VII
- Area of a Triangle
- (i) For any integer a, what is (–1) × a equal to?
(ii) Determine the integer whose product with (–1) is
(a) –22
(b) 37
(c) 0- CBSE Class VII
- Properties Of Multiplication Of Integers
- What letters of the English alphabet have reflectional symmetry (i.e., symmetry related to mirror reflection) about.
- a vertical mirror
- a horizontal mirror
- both horizontal and vertical mirrors
- CBSE Class VII
- Lines Of Symmetry For Regular Polygons
- In a class test (+3) marks are given for every correct answer and (–2) marks are given for every incorrect answer and no marks for not attempting any question. (i) Radhika scored 20 marks. If she has got 12 correct answers, how many questions has she attempted incorrectly? (ii) Mohini scores –5 marks in this test, though she has got 7 correct answers. How many questions has she attempted incorrectly?
- CBSE Class VII
- Properties Of Division Of Integers
- Find the value of:
(i) -4÷\(\frac{2}{3}\)
(ii) -\(\frac{3}{5}\)÷2
(iii) -\(\frac{4}{5}\)÷(-3)
(iv) -\(\frac{1}{8}\)÷\(\frac{3}{4}\)
(v) -\(\frac{2}{13}\)÷\(\frac{1}{7}\)
(vi) -\(\frac{7}{12}\)÷(-\(\frac{2}{13}\))
(vii) \(\frac{3}{13}\)÷(-\(\frac{4}{65}\))- CBSE Class VII
- Operations On Rational Numbers
View More Questions