Question:

Solve the following equations: 
(a) 10p = 100
(b) 10p + 10 = 100
(c)\(\frac{p}{4}\)=5
(d) \(\frac{-p}{3}\)=5
(e)\(\frac{3p}{4}\)=6
(f)3s=-9
(g)3s+12=0
(h)3s=0
(i)2q=6
(j)2q-6=0
(k)2q+6=0
(l)2q+6=12

Updated On: May 24, 2024
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

(a) 10p = 100
\(\Rightarrow\)\(\frac{10p}{10}=\frac{100}{10}\)[Dividing both sides by 10] 
\(\Rightarrow\)\(p=10\)


(b) 10p + 10 = 100
\(\Rightarrow\)10p + 10-10= 100-10
\(\Rightarrow\)\(10p=90\)
\(\Rightarrow\)\(\frac{10p}{10}=\frac{90}{10}\)


(c) \(\frac{p}{4}\)=5
\(\frac{p}{4}\times 4=5\times 4\)
\(p=20\)


(d) \(\frac{-p}{3}\)=5
\(\frac{-p}{3}\times -3\)= 5\(\times-3\)
\(p=-15\)


(e) \(\frac{3p}{4}\)=6
\(\frac{3p}{4}\times 4\)=6\(\times 4\)
\(3p=24\)
\(\frac{3p}{3}=\frac{24}{3}\)

Was this answer helpful?
1
0

Top Questions on A Mind-Reading Game

View More Questions

Questions Asked in CBSE Class VII exam

View More Questions