(i) 3x–5–x+9 = 3x-x-5+9 = 2x+4 = 2×3+4 = 6+4 = 10 [putting a = 3]
(ii) 2–8x+4x+4 = -8x+4x+2+4 = -4x+6 = -4×3+6 = -12+6 = -12 [putting a = 3]
(iii) 3a+5–8a+1 = 3a-8a+5+1 = -5a+6 = -5(-1)+6 = 5+6 = 11 [putting a = -1]
(iv) 10–3b–4–5b = -3b-5b+10-4 = -8b+6 = -8(-2)+6 = 16+6 = 22 [putting a = -2]
(v) 2a–2b–4–5+a = 2a+a-2b-4-5 = 3a-2b-9 = 3(-1)-2(-2)-9 = -3+4-9 = -8 [putting a = -1, b = -2]
If \( x, y \) are two positive integers such that \( x + y = 20 \) and the maximum value of \( x^3 y \) is \( k \) at \( x = a, y = \beta \), then \( \frac{k}{\alpha^2 \beta^2} = ? \)