Total number of books shyam had,
X = 120, Y = (1.1 x 120) = 132, Z = (0.9 x 120) = 108
Total number of books he tore,
X = 5\(\%\) of X = (0.05 x 120) = 6
Y = 10\(\%\) of Y = (0.1 X 132) = 13.2
Z = 15\(\%\) of Z = (0.15 x 108) = 16.2
Percentage of books he tore,
⇒ \(\frac{6+13.2+16.2}{12+132+108}\) x 100
⇒ \(\frac{35.4}{360}\) x 100 = 9.83\(\%\)
Hence, option D is the correct answer. The correct option is (D): None of these