First, we have to show that \((i) ⇔ (ii).\)
Let \(A ⊂ B\)
To show: \(A – B \ne\phi\)
If possible, suppose \(A – B \ne\phi\)
This means that there exists \(x ∈ A, x ≠ B\), which is not possible as \(A ⊂ B.\)
\(∴ A – B = \phi\)
\(∴ A ⊂ B ⇒ A – B = \phi\)
Let \(A – B = \phi\)
To show: \(A ⊂ B\)
Let \(x ∈ A\)
Clearly, \(x ∈ B\) because if \(x ∉ B\), then \(A – B ≠ \phi\)
\(∴ A – B = \phi ⇒ A ⊂ B\)
\(∴ (i) ⇔ (ii)\)
Let \(A ⊂ B\)
To show: \(A ∪ B = B\)
Clearly, \(B ⊂ A ∪ B\)
Let \(x ∈ A ∪ B\)
\(⇒ x ∈ A \space or x ∈ B\)
Case I: \(x ∈ A\)
\(⇒ x ∈ B [∴ A ⊂ B]\)
\(∴ A ∪ B ⊂ B\)
Case II: \(x ∈ B\)
Then, \(A ∪ B = B\)
Conversely, let \(A ∪ B = B\)
Let \(x ∈ A\)
\(⇒ x ∈ A ∪ B\) \([∴ A ⊂ A ∪ B]\)
\(⇒ x ∈ B\) \([ ∴ A ∪ B = B]\)
\(∴ A ⊂ B\)
Hence, \((i) ⇔ (iii)\)
Now, we have to show that \((i) ⇔ (iv).\)
Let \(A ⊂ B\)
Clearly \(A ∩ B ⊂ A\)
Let \(x ∈ A\)
We have to show that \(x ∈ A ∩ B\)
As \(A ⊂ B, x ∈ B\)
\(∴ x ∈ A ∩ B\)
\(∴ A ⊂ A ∩ B\)
Hence, \(A = A ∩ B\)
Conversely, suppose. \(A ∩ B = A\)
Let \(x ∈ A\)
\(⇒ x ∈ A ∩ B\)
\(⇒ x ∈ A\) and \(x ∈ B\)
\(⇒ x ∈ B\)
\(∴ A ⊂ B\)
Hence, \((i) ⇔ (iv).\)
Give reasons for the following.
(i) King Tut’s body has been subjected to repeated scrutiny.
(ii) Howard Carter’s investigation was resented.
(iii) Carter had to chisel away the solidified resins to raise the king’s remains.
(iv) Tut’s body was buried along with gilded treasures.
(v) The boy king changed his name from Tutankhaten to Tutankhamun.
Find the mean deviation about the median for the data
xi | 15 | 21 | 27 | 30 | 35 |
fi | 3 | 5 | 6 | 7 | 8 |
Some important operations on sets include union, intersection, difference, and the complement of a set, a brief explanation of operations on sets is as follows:
1. Union of Sets:
2. Intersection of Sets:
3.Set Difference:
4.Set Complement: