The question involves understanding the genotype-phenotype relationship in sickle cell anaemia. Let's explore each option:
Thus, the correctly matched pairs about sickle cell anaemia are (B), (C) and (D).
(A) HbA HbA : Diseased phenotype
This pair is incorrect. The genotype HbA HbA (homozygous for normal hemoglobin) results in a normal phenotype, not a diseased one.
(B) HbA HbS : Diseased phenotype
This pair is correct. The genotype HbA HbS (heterozygous for sickle cell trait) results in a carrier phenotype, not a diseased one. Carriers typically do not show severe symptoms of sickle cell disease.
(C) HbS HbS : Diseased phenotype
This pair is correct. The genotype HbS HbS (homozygous for sickle cell hemoglobin) results in a diseased phenotype, characterized by sickle cell anemia.
(D) HbS HbA : Carrier of disease
This pair is correct. The genotype HbS HbA (heterozygous for sickle cell trait) results in a carrier phenotype. Carriers are typically healthy but can pass the sickle cell gene to their offspring.
Conclusion
The correct answer is (3) (B), (C) and (D) only. These pairs correctly describe the genotypes and their corresponding phenotypes in sickle cell anaemia.
If a heterozygous tall plant (Tt) is crossed with a dwarf plant (tt), what will be the phenotypic ratio of the offspring?
Study the cross given below:
Identify the abnormalities ‘1’ and ‘2’ in the offsprings of a cross done between a couple and distinguish between them.
The following data shows the number of students in different streams in a school:
Which type of graph is best suited to represent this data?
What comes next in the series?
\(2, 6, 12, 20, 30, \ ?\)