From the figure, it can be observed that gaps between 1st and last sapling = 3
Length of 1 gap = \(\frac{3}{4}\) m
Therefore, the distance between I and IV saplings = 3 × \(\frac{3}{4}\) = \(\frac{9}{4}\) = 2 \(\frac{1}{4}\)m
Match the items given in Column I with one or more items of Column II.
Column I | Column II |
(a) A plane mirror | (i) Used as a magnifying glass. |
(b) A convex mirror | (ii) Can form image of objects spread over a large area. |
(c) A convex lens | (iii) Used by dentists to see enlarged image of teeth. |
(d) A concave mirror | (iv) The image is always inverted and magnified. |
(e) A concave lens | (v) The image is erect and of the same size as the object. |
- | (vi) The image is erect and smaller in size than the object. |