To find the sacrificing ratio of S and T, we first need to calculate their original profit shares and the shares they surrender.
1. Original Shares:
S's share = $\frac{3}{5}$ (since 3 + 2 = 5)
T's share = $\frac{2}{5}$ 2. Shares Surrendered:
S surrenders $\frac{1}{4}$ of his share: \[ \text{S's surrender} = \frac{1}{4} \times \frac{3}{5} = \frac{3}{20} \]
T surrenders $\frac{1}{3}$ of his share: \[ \text{T's surrender} = \frac{1}{3} \times \frac{2}{5} = \frac{2}{15} \] 3. Finding the Sacrificing Ratio: To find the sacrificing ratio, we need a common denominator. The LCM of 20 and 15 is 60. - Convert S's surrender: \[ \frac{3}{20} = \frac{9}{60} \] - Convert T's surrender: \[ \frac{2}{15} = \frac{8}{60} \] 4. Sacrificing Ratio: The sacrificing ratio of S and T: \[ \text{Sacrificing ratio} = \frac{\text{S's surrender}}{\text{T's surrender}} = \frac{9}{8} = 9 : 8 \] Thus, the sacrificing ratio of S and T will be 9 : 8.
S and T are partners in a firm sharing profits in the ratio of 3:2. They admit U as a new partner. S surrenders 1/4 of his share and T surrenders 1/3 of his share in favour of U. We need to calculate the sacrificing ratio of S and T.
Step 1: Calculate the amount of share surrendered by S and T.
Step 2: Calculate the surrendered share by S:
S surrenders 1/4 of his share. Therefore, the surrendered amount from S is:
S's surrendered share = (1/4) × (3/5) = 3/20
Step 3: Calculate the surrendered share by T:
T surrenders 1/3 of his share. Therefore, the surrendered amount from T is:
T's surrendered share = (1/3) × (2/5) = 2/15
Step 4: Find the sacrificing ratio of S and T.
The sacrificing ratio is the ratio of the shares surrendered by S and T. To find the ratio, we first need to express both surrendered shares with a common denominator.
S's surrendered share = 3/20
T's surrendered share = 2/15 The LCM of 20 and 15 is 60.
So, we convert both fractions to have the denominator 60:S's surrendered share = (3/20) × (3/3) = 9/60
T's surrendered share = (2/15) × (4/4) = 8/60
Therefore, the sacrificing ratio of S and T is:Sacrificing ratio = 9:8
Thus, the correct answer is: (A) 9:8
Match List-I with List-II
\[\begin{array}{|l|l|} \hline \text{List-I (Soil component)} & \text{List-II (Definition)} \\ \hline (A)~\text{Azonal soils} & (I)~\text{An individual natural aggregate of soil particles.} \\ (B)~\text{Regoliths} & (II)~\text{Organisms living in the soil or ground} \\ (C)~\text{Ped} & (III)~\text{Soils have uniformity from the top-surface to the base, and do not have well-developed soil horizons.} \\ (D)~\text{Edaphons} & (IV)~\text{Zone of loose and unconsolidated weathered rock materials.} \\ \hline \end{array}\]
Choose the correct answer from the options given below:
Match List-I with List-II
\[\begin{array}{|l|l|} \hline \text{List I Content of humus} & \text{List II Percentage of contents} \\ \hline \text{(A) Carbon} & \text{(I) 35-40\%} \\ \hline \text{(B) Oxygen} & \text{(II) ~5\%} \\ \hline \text{(C) Hydrogen} & \text{(III) 55-60\%} \\ \hline \text{(D) Nitrogen} & \text{(IV) 15\%} \\ \hline \end{array}\]
Choose the correct answer from the options given below: