Question:

Ronnic has a bag containing 7 red and 9 green balls. From it, he draws out 6 balls simultaneously at random. The probability that 4 of them are red and the rest are green is

  • \(\frac{24}{143}\)
  • \(\frac{45}{286}\)
  • \(\frac{155}{2001}\)
  • \(\frac{302}{1005}\)
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The Correct Option is B

Solution and Explanation

The correct option is (B):\(\frac{45}{286}\).
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