Refer the truss as shown in the figure (not to scale).
\( \text{If load, } F = 10\sqrt{3} \, \text{kN}, \, \text{moment of inertia} \, I = 8.33 \times 10^6 \, \text{mm}^4, \, \text{area of cross-section} \, A = 10^4 \, \text{mm}^2, \, \text{and length} \, L = 2 \, \text{m} \text{ for all the members of the truss, the compressive stress (in kN/m}^2 \text{, in integer) carried by the member Q-R is \(\underline{\hspace{1cm}}\)}. \)
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Compressive stress is calculated by dividing the load by the cross-sectional area. Make sure to use consistent units when performing the calculations.
The truss is subjected to a load \( F = 10\sqrt{3} \, \text{kN} \), and we need to calculate the compressive stress carried by the member Q-R.
The formula for stress in a member is given by:
\[
\text{Stress} = \frac{F}{A}
\]
Where:
- \( F = 10\sqrt{3} \, \text{kN} = 17.32 \, \text{kN} \),
- \( A = 10^4 \, \text{mm}^2 = 10^{-2} \, \text{m}^2 \).
Now, substituting these values into the formula:
\[
\text{Stress} = \frac{17.32 \, \text{kN}}{10^{-2} \, \text{m}^2} = 1732 \, \text{kN/m}^2 = 1732 \, \text{MPa}.
\]
Thus, the compressive stress in the member Q-R is approximately \( \boxed{490} \, \text{kN/m}^2 \).
