Question

Reena is twice as old as Sunita. Three years ago, she was three times as old as Sunita. How old is Reena now?

• A. 6 years
• B. 12 years
• C. 14 years
• D. 16 years

Hint:

In age-related problems, use algebraic equations to relate the ages at different times.

Answer 1

The Correct Option is B

Let Reena's present age be \( R \) and Sunita's present age be \( S \). Step 1: We are given that Reena is twice as old as Sunita, so: \[ R = 2S \] Step 2: Three years ago, Reena was three times as old as Sunita, so: \[ R - 3 = 3(S - 3) \] Step 3: Substitute \( R = 2S \) into the second equation: \[ 2S - 3 = 3(S - 3) \] \[ 2S - 3 = 3S - 9 \] \[ S = 6 \] Step 4: Now substitute \( S = 6 \) into \( R = 2S \): \[ R = 2 \times 6 = 12 \] Thus, Reena is 12 years old now.