Question:

Ratio of number of oxygen atoms in $Ca_3(PO_4)_2$ and $H_3PO_3$, if both contain same number of $P$ atoms, is

Updated On: Jul 6, 2022
  • $3 : 4$
  • $4 : 3$
  • $2 : 3$
  • $3 : 2$
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The Correct Option is B

Solution and Explanation

$1$ molecule of $Ca_3(PO_4)_2$ contains $2$ atoms, of $P$ and $1$ molecule of $H_3PO_3$ contains $1$ atom of $P$. So, $0.5$ molecule of $Ca_3(PO_4)_2$ and $1$ molecule of $H_3PO_3$ contain equal number of $P$ atoms. Number of oxygen atoms in $0.5$ molecule of $Ca_3(PO_4)_2 = 0.5 \times 8 = 4$ And in $1$ molecule $H_3PO_3 = 3$
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Notes on p -Block Elements

Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: