Question:
Ratio of number of oxygen atoms in $Ca_3(PO_4)_2$ and $H_3PO_3$, if both contain same number of $P$ atoms, is
Ratio of number of oxygen atoms in $Ca_3(PO_4)_2$ and $H_3PO_3$, if both contain same number of $P$ atoms, is
Updated On: Jul 6, 2022
- $3 : 4$
- $4 : 3$
- $2 : 3$
- $3 : 2$
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The Correct Option is B
Solution and Explanation
$1$ molecule of $Ca_3(PO_4)_2$ contains $2$ atoms, of $P$ and $1$ molecule of $H_3PO_3$ contains $1$ atom of $P$.
So, $0.5$ molecule of $Ca_3(PO_4)_2$ and $1$ molecule of $H_3PO_3$
contain equal number of $P$ atoms.
Number of oxygen atoms in
$0.5$ molecule of $Ca_3(PO_4)_2 = 0.5 \times 8 = 4$
And in $1$ molecule $H_3PO_3 = 3$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family