Question:

Rate of radiation by a black body is $R$ at temperature $T$. Another body has the same area but emissivity is $0.2$ and temperature is $3T$. Its rate of radiation is

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Radiated power varies as the fourth power of absolute temperature.
Updated On: Feb 4, 2026
  • $(8.1)R$
  • $(16.2)R$
  • $(24.3)R$
  • $(32.4)R$
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The Correct Option is B

Solution and Explanation

Step 1: Apply Stefan–Boltzmann law.
The power radiated is given by: \[ P = e \sigma A T^4 \] Step 2: Radiation from black body.
For a black body, emissivity $e = 1$, hence: \[ R = \sigma A T^4 \] Step 3: Radiation from second body.
\[ P' = 0.2 \times \sigma A (3T)^4 \] Step 4: Simplification.
\[ P' = 0.2 \times 81 \times \sigma A T^4 = 16.2 \sigma A T^4 \] Step 5: Final comparison.
\[ P' = 16.2R \]
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