Comprehension
Question is based on following passage:
p-block elements are placed in groups 13 to 18 of the periodic table. Group 15 is nitrogen family. Nitrogen makes various compounds like $NH_3, HNO_3, N_2O, NO_2$, etc. Phosphorus exists in the form of white and red phosphorus. White phosphorus glows in dark. $PH_3$, gas is used as smoke screen. Group 16 is called oxygen family. Dry air contains 21% $O_2$ gas by volume. Combined sulphur exists as sulphates such as gypsum, epsome salt, baryte etc. The allotropic forms of sulphur are Rhombic and monoclinic sulphur. $S_2$ is paramagnetic like $O_2$, and it stable at high temperature. Group 17 is Halogen family. $F_2,$ is highly reactive, $Cl_2$, is greenish yellow gas. Both $SO_2$, and $Cl_2$ are used for bleaching. Group 18 is Noble gas family but some noble gases also form compounds. Complete hydrolysis of $XeF_6$, gives HF and $XeO_6$, as main products.
p-block elements are placed in groups 13 to 18 of the periodic table. Group 15 is nitrogen family. Nitrogen makes various compounds like $NH_3, HNO_3, N_2O, NO_2$, etc. Phosphorus exists in the form of white and red phosphorus. White phosphorus glows in dark. $PH_3$, gas is used as smoke screen. Group 16 is called oxygen family. Dry air contains 21% $O_2$ gas by volume. Combined sulphur exists as sulphates such as gypsum, epsome salt, baryte etc. The allotropic forms of sulphur are Rhombic and monoclinic sulphur. $S_2$ is paramagnetic like $O_2$, and it stable at high temperature. Group 17 is Halogen family. $F_2,$ is highly reactive, $Cl_2$, is greenish yellow gas. Both $SO_2$, and $Cl_2$ are used for bleaching. Group 18 is Noble gas family but some noble gases also form compounds. Complete hydrolysis of $XeF_6$, gives HF and $XeO_6$, as main products.
Question: 1
Match List -I with List-II List -I List-II A Ammonia I Rotten fish small B Nitric Acid II Detection of metal ions C Phosphene III Chemiluminescence D White Phosphorus IV Ostwald Process
Choose the correct answer from the options given below:
Match List -I with List-II
Choose the correct answer from the options given below:
| List -I | List-II | ||
| A | Ammonia | I | Rotten fish small |
| B | Nitric Acid | II | Detection of metal ions |
| C | Phosphene | III | Chemiluminescence |
| D | White Phosphorus | IV | Ostwald Process |
Updated On: Sep 19, 2024
- (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
- (A)-(I), (B)-(IV), (C)-(III), (D)-(II)
- (A)-(I), (B)-(II), (C)-(IV), (D)-(III)
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The Correct Option is A
Solution and Explanation
The correct option is (A) : (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
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Question: 2
Sulphate of magnesium of the following is:
Sulphate of magnesium of the following is:
Updated On: Sep 19, 2024
- Gypsum
- Epsom salt
- Baryte
- Galena
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The Correct Option is B
Solution and Explanation
The correct option is (B) : Epsom salt
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Question: 3
At elevated temperature (~ 1000 K) the dominant form of sulphur is:
At elevated temperature (~ 1000 K) the dominant form of sulphur is:
Updated On: Sep 19, 2024
- Rhombic Sulphur
- Monoclinic Sulphur
- $S_8$ molecules
- $S_2$
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The Correct Option is D
Solution and Explanation
The correct option is (D) : $S_2$
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Question: 4
The permanent bleaching effect is caused by:
The permanent bleaching effect is caused by:
Updated On: Sep 19, 2024
- Chlorine gas
- $SO_2$ gas
- Aqua Regia
- $COCI_2$
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The Correct Option is A
Solution and Explanation
The correct option is (A) : Chlorine gas
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Question: 5
The product of complete hydrolysis of $XeF_6$ in the following reaction is
$XeF_6+H_2O → ?+ HF$
The product of complete hydrolysis of $XeF_6$ in the following reaction is
$XeF_6+H_2O → ?+ HF$
$XeF_6+H_2O → ?+ HF$
Updated On: Sep 19, 2024
- $XeOF_4$
- $XeO_2F_2$
- $XeO_3$
- Xe
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The Correct Option is C
Solution and Explanation
The correct option is (C) : $XeO_3$
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Top Questions on p -Block Elements
- $\textbf{Choose the correct statements about the hydrides of group 15 elements.}$
A. The stability of the hydrides decreases in the order \(\text{NH}_3 > \text{PH}_3 > \text{AsH}_3 > \text{SbH}_3 > \text{BiH}_3\)
B. The reducing ability of the hydrides increases in the order \(\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3\)
C. Among the hydrides, \(\text{NH}_3\) is a strong reducing agent while \(\text{BiH}_3\) is a mild reducing agent.
D. The basicity of the hydrides increases in the order \(\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3\)
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(B) Non metals have lower ionisation enthalpy than metals.
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