Question

Quantity A: The area of 4 squares with 3 inches of side.
Quantity B: The area of 3 squares with 4 inches of side.

• A. If Quantity A is more than Quantity B
• B. If Quantity A is equal to Quantity B
• C. If Quantity A is less than Quantity B
• D. If comparison can’t be made from the information given

Hint:

When comparing areas of squares, use the formula \( \text{Area} = \text{side}^2 \) and then multiply by the number of squares.

Answer 1

The Correct Option is C

Step 1: Calculate the area of one square with 3 inches side.
The area of a square is given by the formula \( \text{Area} = \text{side}^2 \). For Quantity A: \[ \text{Area of one square} = 3^2 = 9 \text{ square inches}. \] Thus, the area of 4 squares with a side of 3 inches is: \[ \text{Total area of 4 squares} = 4 \times 9 = 36 \text{ square inches}. \] Step 2: Calculate the area of one square with 4 inches side.
For Quantity B: \[ \text{Area of one square} = 4^2 = 16 \text{ square inches}. \] Thus, the area of 3 squares with a side of 4 inches is: \[ \text{Total area of 3 squares} = 3 \times 16 = 48 \text{ square inches}. \] Step 3: Comparison.
We have: - Quantity A = 36 square inches - Quantity B = 48 square inches Since \( 36<48 \), Quantity A is less than Quantity B. Step 4: Conclusion.
Therefore, the correct answer is option (3): Quantity A is less than Quantity B.