Prove that the function f(x) = xn, is continuous at x = n, where n is a positive integer.
The given function is f (x)=xn
It is evident that f is defined at all positive integers,n,and its value at n is nn.
Then, \(\lim\limits_{x \to n}\) f(n) = \(\lim\limits_{x \to n}\) f(xn) = nn
∴\(\lim\limits_{x \to n}\) f(x) = f(n)
Therefore, f is continuous at n, where n is a positive integer.
The function \( f(x) \) is defined as follows: \[ f(x) = \begin{cases} 2+x, & \text{if } x \geq 0 \\ 2-x, & \text{if } x \leq 0 \end{cases} \] Then function \( f(x) \) at \( x=0 \) is:
A function is said to be continuous at a point x = a, if
limx→a
f(x) Exists, and
limx→a
f(x) = f(a)
It implies that if the left hand limit (L.H.L), right hand limit (R.H.L) and the value of the function at x=a exists and these parameters are equal to each other, then the function f is said to be continuous at x=a.
If the function is undefined or does not exist, then we say that the function is discontinuous.
Conditions for continuity of a function: For any function to be continuous, it must meet the following conditions: