Question:

Prove that the function f(x) = xn, is continuous at x = n, where n is a positive integer.

Updated On: Aug 29, 2023
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Solution and Explanation

The given function is f (x)=xn
It is evident that f is defined at all positive integers,n,and its value at n is nn.

Then, \(\lim\limits_{x \to n}\) f(n) = \(\lim\limits_{x \to n}\) f(xn) = nn
\(\lim\limits_{x \to n}\) f(x) = f(n)

Therefore, f is continuous at n, where n is a positive integer.

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Concepts Used:

Continuity

A function is said to be continuous at a point x = a,  if

limx→a

f(x) Exists, and

limx→a

f(x) = f(a)

It implies that if the left hand limit (L.H.L), right hand limit (R.H.L) and the value of the function at x=a exists and these parameters are equal to each other, then the function f is said to be continuous at x=a.

If the function is undefined or does not exist, then we say that the function is discontinuous.

Conditions for continuity of a function: For any function to be continuous, it must meet the following conditions:

  • The function f(x) specified at x = a, is continuous only if f(a) belongs to real number.
  • The limit of the function as x approaches a, exists.
  • The limit of the function as x approaches a, must be equal to the function value at x = a.