\(L.H.S=\frac{cos({\pi}+x)cos(-x)}{sin({\pi}-x)cos(\frac{\pi}{2}+x)}\)
\(=\frac{[-cos\,x][cos\,x]}{(sin\,x)(-sin\,x)}\)
\(\frac{-cos^2x}{-sin^2x}\)
\(=cot^2x\)
\(=R.H.S.\)
Prove that. \(sin^2 \frac{π}{6}+cos^2 \frac{π}{3}–tan^2 \frac{π}{4}=-\frac{1}{2}\)
Figures 9.20(a) and (b) refer to the steady flow of a (non-viscous) liquid. Which of the two figures is incorrect ? Why ?