Question:

Probability of getting positive integral roots of the equation \(x^2-n=0\) for the integer \(n,\ 1\le n \le 40\) is

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For integer roots of \(x^2=n\), \(n\) must be a perfect square.
Updated On: Jan 3, 2026
  • \(\frac{1}{5}\)
  • \(\frac{1}{10}\)
  • \(\frac{3}{20}\)
  • \(\frac{1}{20}\)
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The Correct Option is C

Solution and Explanation

Step 1: Condition for positive integral roots.
Equation:
\[ x^2-n=0 \Rightarrow x=\pm\sqrt{n} \]
Roots are integers only if \(n\) is a perfect square.
Step 2: Count perfect squares between 1 and 40.
Perfect squares \(\le 40\):
\[ 1,4,9,16,25,36 \]
Total = 6 numbers.
Step 3: Total possible values of \(n\).
\[ n=1,2,3,\ldots,40 \Rightarrow 40 \text{ outcomes} \]
Step 4: Probability.
\[ P=\frac{6}{40}=\frac{3}{20} \]
Final Answer:
\[ \boxed{\frac{3}{20}} \]
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