a. \(x\) =\(-2\sin\bigg(3t+\frac{\pi}{3}\bigg)+2\cos\bigg(3t+\frac{\pi}{3}+\frac{\pi}{2}\bigg)\)
= \(2\cos\bigg(3t+\frac{5\pi}{6}\bigg)\)
If this equation is compared with the standard SHM equation \(x\) =\(A\cos\bigg(\frac{2π}{T} t+\phi\bigg)\) , then we get:
Amplitude, \(A\) = \(2 \;cm\)
Phase angle, \(\phi\) = \(\frac{5\pi}{6}\)=\(150º\)
Angular velocity, \(\omega\) = \(\frac{2\pi}{T}\)=\(3 \,rad/sec.\)
The motion of the particle can be plotted as shown in the following figure.
\(x\) =\(\cos\bigg(\frac{\pi}{6}-t\bigg)\)=\(\cos \bigg(t-\frac{π}{6}\bigg)\)
If this equation is compared with the standard SHM equation \(x\) =\(A\cos\bigg(\frac{2\pi}{T} t+\phi\bigg)\), then we get :
Amplitude, \(A\) =\(1\)
Phase angle, \(\phi\) = \(-\frac{π}{6}\)=\(-30º\)
Angular velocity, \(\omega\) = \(\frac{2\pi}{T}\)=\(1 \;rad/s\)
The motion of the particle can be plotted as shown in the following figure.
\(x\) = \(3\sin\bigg(2\pi t+\frac{\pi}{4}\bigg)\)
=\(-3\cos\bigg[\bigg(2\pi t+\frac{\pi}{4}\bigg)+\frac{\pi}{2}\bigg]\)=-\(3\cos\bigg(2\pi t+\frac{3\pi}{4}\bigg)\)
If this equation is compared with the standard SHM equation \(x\) = \(A\cos\bigg(\frac{2\pi}{T} t+\phi\bigg)\) , then we get:
Amplitude, \(A\) = \(3 \,cm\)
Phase angle, \(\phi\) = \(\frac{3\pi}4\)=\(135º\)
Angular velocity, \(\omega\) =\(\frac{2\pi}{T}\) = \(2\pi \;rad/s\)
The motion of the particle can be plotted as shown in the following figure.
\(x\) = \(2 \cos \pi t\)
If this equation is compared with the standard SHM equation we get: \(A\cos\bigg(\frac{2\pi}{T} t+\phi\bigg)\) then we get:
Amplitude, \(A\) = \(2 \;cm\)
Phase angle, \(\phi\) = \(0\)
Angular velocity, \(\omega\) = \(\pi \; rad/s\)
The motion of the particle can be plotted as shown in the following figure.
Figure 14.30 (a) shows a spring of force constant k clamped rigidly at one end and a mass attached to its free end. A force F applied at the free end stretches the spring. Figure 14.30 (b) shows the same spring with both ends free and attached to a mass m , then clamped rigidly at one end and a mass at either end. Each end of the spring in Fig. 14.30(b) is stretched by the same force F.
What is the maximum extension of the spring in the two cases?
If the mass in Fig. (a) and the two masses in Fig. (b) are released, what is the period of oscillation in each case?
Figures 9.20(a) and (b) refer to the steady flow of a (non-viscous) liquid. Which of the two figures is incorrect ? Why ?
Simple Harmonic Motion is one of the most simple forms of oscillatory motion that occurs frequently in nature. The quantity of force acting on a particle in SHM is exactly proportional to the displacement of the particle from the equilibrium location. It is given by F = -kx, where k is the force constant and the negative sign indicates that force resists growth in x.
This force is known as the restoring force, and it pulls the particle back to its equilibrium position as opposing displacement increases. N/m is the SI unit of Force.
When a particle moves to and fro about a fixed point (called equilibrium position) along with a straight line then its motion is called linear Simple Harmonic Motion. For Example spring-mass system
The restoring force or acceleration acting on the particle should always be proportional to the displacement of the particle and directed towards the equilibrium position.
When a system oscillates angular long with respect to a fixed axis then its motion is called angular simple harmonic motion.
The restoring torque (or) Angular acceleration acting on the particle should always be proportional to the angular displacement of the particle and directed towards the equilibrium position.
Τ ∝ θ or α ∝ θ
Where,