Question:

Plot the corresponding reference circle for each of the following simple harmonic motions. Indicate the initial (t = 0) position of the particle, the radius of the circle, and the angular speed of the rotating particle. For simplicity, the sense of rotation may be fixed to be anticlockwise in every case: ( x is in cm and t is in s).
  1. x = –2 sin (3t + \(\frac{\pi}{3}\))
  2. x = cos (\(\frac{\pi}{6}\) – t)
  3. x = 3 sin (2πt + \(\frac{\pi}{4}\))
  4. x = 2 cos πt 

     

Updated On: Nov 20, 2023
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Solution and Explanation

a. \(x\) =\(-2\sin\bigg(3t+\frac{\pi}{3}\bigg)+2\cos\bigg(3t+\frac{\pi}{3}+\frac{\pi}{2}\bigg)\)
\(2\cos\bigg(3t+\frac{5\pi}{6}\bigg)\)
If this equation is compared with the standard SHM equation \(x\) =\(A\cos\bigg(\frac{2π}{T} t+\phi\bigg)\) , then we get:
Amplitude, \(A\) = \(2 \;cm\)
Phase angle, \(\phi\) = \(\frac{5\pi}{6}\)=\(150º\)
Angular velocity, \(\omega\) = \(\frac{2\pi}{T}\)=\(3 \,rad/sec.\)
The motion of the particle can be plotted as shown in the following figure.
The motion of the particle
\(x\) =\(\cos\bigg(\frac{\pi}{6}-t\bigg)\)=\(\cos \bigg(t-\frac{π}{6}\bigg)\)
If this equation is compared with the standard SHM equation \(x\) =\(A\cos\bigg(\frac{2\pi}{T} t+\phi\bigg)\), then we get : 
Amplitude, \(A\) =\(1\)
Phase angle, \(\phi\) = \(-\frac{π}{6}\)=\(-30º\)
Angular velocity, \(\omega\) = \(\frac{2\pi}{T}\)=\(1 \;rad/s\)
The motion of the particle can be plotted as shown in the following figure.
The motion of the particle
\(x\) = \(3\sin\bigg(2\pi t+\frac{\pi}{4}\bigg)\)
=\(-3\cos\bigg[\bigg(2\pi t+\frac{\pi}{4}\bigg)+\frac{\pi}{2}\bigg]\)=-\(3\cos\bigg(2\pi t+\frac{3\pi}{4}\bigg)\)
If this equation is compared with the standard SHM equation \(x\) = \(A\cos\bigg(\frac{2\pi}{T} t+\phi\bigg)\) , then we get:
Amplitude, \(A\) = \(3 \,cm\)
Phase angle, \(\phi\) = \(\frac{3\pi}4\)=\(135º\)
Angular velocity, \(\omega\) =\(\frac{2\pi}{T}\) = \(2\pi \;rad/s\)
The motion of the particle can be plotted as shown in the following figure.
The motion of the particle
\(x\) = \(2 \cos \pi t\) 
If this equation is compared with the standard SHM equation we get: \(A\cos\bigg(\frac{2\pi}{T} t+\phi\bigg)\) then we get:
Amplitude, \(A\) = \(2 \;cm\) 
Phase angle, \(\phi\) = \(0\) 
Angular velocity, \(\omega\) = \(\pi \; rad/s\) 
The motion of the particle can be plotted as shown in the following figure.

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Concepts Used:

Simple Harmonic Motion

Simple Harmonic Motion is one of the most simple forms of oscillatory motion that occurs frequently in nature. The quantity of force acting on a particle in SHM is exactly proportional to the displacement of the particle from the equilibrium location. It is given by F = -kx, where k is the force constant and the negative sign indicates that force resists growth in x.

This force is known as the restoring force, and it pulls the particle back to its equilibrium position as opposing displacement increases. N/m is the SI unit of Force.

Types of Simple Harmonic Motion

Linear Simple Harmonic Motion:

When a particle moves to and fro about a fixed point (called equilibrium position) along with a straight line then its motion is called linear Simple Harmonic Motion. For Example spring-mass system

Conditions:

The restoring force or acceleration acting on the particle should always be proportional to the displacement of the particle and directed towards the equilibrium position.

  • – displacement of particle from equilibrium position.
  • – Restoring force
  • - acceleration

Angular Simple Harmonic Motion:

When a system oscillates angular long with respect to a fixed axis then its motion is called angular simple harmonic motion.

Conditions:

The restoring torque (or) Angular acceleration acting on the particle should always be proportional to the angular displacement of the particle and directed towards the equilibrium position.

Τ ∝ θ or α ∝ θ

Where,

  • Τ – Torque
  • α angular acceleration
  • θ – angular displacement