Question:

Plasmid pBR322 has PstI restriction enzyme site within gene ampR that confers ampicillin resistance. If this enzyme is used for inserting a gene for β-galactoside production and the recombinant plasmid is inserted in an E.coli strain

Updated On: Nov 13, 2025
  • it will be able to produce a novel protein with dual ability.
  • it will not be able to confer ampicillin resistance to the host cell.
  • the transformed cells will have the ability to resist ampicillin as well as produce β-galactoside.
  • it will lead to lysis of host cell.
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The Correct Option is B

Solution and Explanation

The question pertains to the genetic engineering concept involving plasmid vectors and restriction enzymes. Let's understand the situation:

  1. Plasmid pBR322 is commonly used as a cloning vector in molecular biology. It carries two sets of antibiotic resistance genes: one for ampicillin (ampR) and the other for tetracycline (tetR).
  2. The PstI restriction enzyme cuts the plasmid at a specific site within the ampR gene.
  3. In this scenario, PstI is used to insert a foreign gene (in this case, the gene for β-galactoside production) into the plasmid. The insertion disrupts the ampR gene because it occurs at its locus.
  4. With the ampR gene disrupted, the resulting recombinant plasmid will no longer confer resistance to ampicillin. This means that cells transformed with this plasmid will not survive on a medium containing ampicillin.
  5. However, they will potentially express the β-galactoside gene, assuming the gene is inserted in the correct orientation and under appropriate regulatory controls.

Let's evaluate the options:

  • Option 1: "It will be able to produce a novel protein with dual ability." This is incorrect because while the β-galactoside protein may be produced, the plasmid will lose the ability to confer ampicillin resistance due to the disruption of the ampR gene.
  • Option 2: "It will not be able to confer ampicillin resistance to the host cell." This is correct as the insertion of the gene within the ampR site disrupts ampicillin resistance.
  • Option 3: "The transformed cells will have the ability to resist ampicillin as well as produce β-galactoside." This is incorrect since the ampicillin resistance is lost.
  • Option 4: "It will lead to lysis of host cell." This is incorrect because the process described does not necessarily cause cell lysis.

Based on the explanation, the correct answer is: it will not be able to confer ampicillin resistance to the host cell.

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Concepts Used:

Structure of DNA and RNA

DNA Structure:

Human DNA is unique and is made up of 3 billion base pairs. However, 99% of them are the same in all humans. The sequence of these bases determines what information needs to be coded that is necessary for the organism's growth and development. During the process of transcription (when DNA is replicated), a product is formed known as RNA (Ribonucleic Acid). This RNA is responsible for translating genetic information from DNA to protein followed by reading through ribosomes. 

Read More: Structure of DNA

RNA Structure:

The ribonucleic acid has all the components same to that of the DNA with only 2 main differences within it. RNA has the same nitrogen bases called the adenine, Guanine, Cytosine as that of the DNA except for the Thymine which is replaced by the uracil. Adenine and uracil are considered as the major building blocks of RNA and both of them form base-pair with the help of 2 hydrogen bonds.

RNA resembles a hairpin structure and like the nucleotides in DNA, nucleotides are formed in this ribonucleic material(RNA). Nucleosides are nothing but the phosphate groups which sometimes also helps in the production of nucleotides in the DNA.

Read More: Structure of RNA